tan(-11π/6)、sin(-16π/3)、cos120°、cos(-180°-β)的求解过程.

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tan(-11π/6)、sin(-16π/3)、cos120°、cos(-180°-β)的求解过程.tan(-11π/6)、sin(-16π/3)、cos120°、cos(-180°-β)的求解过程.

tan(-11π/6)、sin(-16π/3)、cos120°、cos(-180°-β)的求解过程.
tan(-11π/6)、sin(-16π/3)、cos120°、cos(-180°-β)的求解过程.

tan(-11π/6)、sin(-16π/3)、cos120°、cos(-180°-β)的求解过程.
tan(-11π/6)= tan(π/6)=√3/3 ,因为tan函数的周期为π
sin(-16π/3)=sin(2/3π)=√3/2 ,sin函数的周期为2π
cos120°=1/2 ,cos(-180°-β)= cos(360°-180°-β)= cos (π-β)= -cos(-β) = -cosβ

tan(-11π/6)= tan(-2π+π/6)=tan(π/6)=√3/3
sin(-16π/3)=sin(-6π+2/3π)=sin(2/3π)=√3/2
cos120°=cos(180-60)=-cos(60)=-1/2 , cos(-180°-β)= cos(360°-180°-β)= cos (π-β)= -cosβ
-11π/6在第一象限

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